11x^2-109x+60=0

Solution for 11x^2-109x+60=0 equation:

11x^2-109x+60=0

a = 11; b = -109; c = +60;
Δ = b2-4ac
Δ = -1092-4·11·60
Δ = 9241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-109)-\sqrt{9241}}{2*11}=\frac{109-\sqrt{9241}}{22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-109)+\sqrt{9241}}{2*11}=\frac{109+\sqrt{9241}}{22}
$